Despite entering the free agent signing period with a league-high $65 million, the Tampa Bay Buccaneers didn't come away with free agency's biggest prize – Tennessee defensive tackle Albert Haynesworth.
Haynesworth, 27, agreed to terms on a blockbuster contract with the Washington Redskins on Friday morning. The seven-year contract is worth $100 million and includes $41 million in guaranteed money in the first three years, according to Haynesworth's agent Chad Speck. Haynesworth will be the highest-paid player in the NFL.
The Bucs were targeting the 6-foot-6, 320-pound Haynesworth because the team has a void at the defensive tackle position in new defensive coordinator Jim Bates' scheme.
Tampa Bay is in the process of attempting to line up visits with several free agents, including Saints linebacker Jonathan Vilma. The team is also attempting to visit with Cardinals defensive end Antonio Smith and Giants running back Derrick Ward, according to ProFootballTalk.com.